Solve {l}{2-5x+8={(2)}{(9x)}}{text{Solvefor}ytext{where}}{y=-19}

$$\left. \begin{array} { l } { 2 - 5 x + 8 = {(2)} {(9 x)} }\\ { \text{Solve for } y \text{ where} } \\ { y = -19 } \end{array} \right.$$

Solve for x, y

$$y=-19$$

Solution Steps

Consider the first equation. Add 2 and 8 to get 10.

$$10-5x=2\times 9x$$

Multiply 2 and 9 to get 18.

$$10-5x=18x$$

Subtract 18x from both sides.

$$10-5x-18x=0$$

Combine -5x and -18x to get -23x.

$$10-23x=0$$

Subtract 10 from both sides. Anything subtracted from zero gives its negation.

$$-23x=-10$$

Divide both sides by -23.

$$x=\frac{-10}{-23}$$

Fraction \frac{-10}{-23} can be simplified to \frac{10}{23} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{10}{23}$$

The system is now solved.

$$x=\frac{10}{23} y=-19$$