Solve {r}{2*3^3-(-1)^4+3*3^2}{*(-1^3)}

$$\left. \begin{array} { r } { 2 \times 3 ^ { 3 } - ( - 1 ) ^ { 4 } + 3 \times 3 ^ { 2 } } \\ { \times ( - 1 ^ { 3 } ) } \end{array} \right.$$

Evaluate

$$26$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2\times 3^{3}-\left(-1\right)^{4}+3^{3}\left(-1^{3}\right)$$

Calculate 3 to the power of 3 and get 27.

$$2\times 27-\left(-1\right)^{4}+3^{3}\left(-1^{3}\right)$$

Multiply 2 and 27 to get 54.

$$54-\left(-1\right)^{4}+3^{3}\left(-1^{3}\right)$$

Calculate -1 to the power of 4 and get 1.

$$54-1+3^{3}\left(-1^{3}\right)$$

Subtract 1 from 54 to get 53.

$$53+3^{3}\left(-1^{3}\right)$$

Calculate 3 to the power of 3 and get 27.

$$53+27\left(-1^{3}\right)$$

Calculate 1 to the power of 3 and get 1.

$$53+27\left(-1\right)$$

Multiply 27 and -1 to get -27.

$$53-27$$

Subtract 27 from 53 to get 26.

$$26$$

Factor

$$2\times 13$$