Solve {r}{128}{+17}{-quad88}{+quad14.5}{divquad2}

$$\left. \begin{array} { r } { 128 } \\ { + 17 } \\ { - \quad 88 } \\ { + \quad 14.5 } \\ { \div \quad 2 } \end{array} \right.$$

Evaluate

$$64.25$$

Solution Steps

Add 128 and 17 to get 145.

$$145-88+\frac{14.5}{2}$$

Subtract 88 from 145 to get 57.

$$57+\frac{14.5}{2}$$

Expand \frac{14.5}{2} by multiplying both numerator and the denominator by 10.

$$57+\frac{145}{20}$$

Reduce the fraction \frac{145}{20} to lowest terms by extracting and canceling out 5.

$$57+\frac{29}{4}$$

Convert 57 to fraction \frac{228}{4}.

$$\frac{228}{4}+\frac{29}{4}$$

Since \frac{228}{4} and \frac{29}{4} have the same denominator, add them by adding their numerators.

$$\frac{228+29}{4}$$

Add 228 and 29 to get 257.

$$\frac{257}{4}$$

Factor

$$\frac{257}{2 ^ {2}} = 64\frac{1}{4} = 64.25$$