Solve {r}{12+4a-b=0}{36-4a=0}

$$\left. \begin{array} { r } { 12 + 4 a - b = 0 } \\ { 36 - 4 a = 0 } \end{array} \right.$$

Solve for a, b

$$a=9$$

$$b=48$$

Solution Steps

Consider the second equation. Subtract 36 from both sides. Anything subtracted from zero gives its negation.

$$-4a=-36$$

Divide both sides by -4.

$$a=\frac{-36}{-4}$$

Divide -36 by -4 to get 9.

$$a=9$$

Consider the first equation. Insert the known values of variables into the equation.

$$12+4\times 9-b=0$$

Multiply 4 and 9 to get 36.

$$12+36-b=0$$

Add 12 and 36 to get 48.

$$48-b=0$$

Subtract 48 from both sides. Anything subtracted from zero gives its negation.

$$-b=-48$$

Divide both sides by -1.

$$b=\frac{-48}{-1}$$

Fraction \frac{-48}{-1} can be simplified to 48 by removing the negative sign from both the numerator and the denominator.

$$b=48$$

The system is now solved.

$$a=9 b=48$$