Solve {r}{(a+1)^2-2(a+1)}{-3}

$$\left. \begin{array} { r } { ( a + 1 ) ^ { 2 } - 2 ( a + 1 ) } \\ { - 3 } \end{array} \right.$$

Evaluate

$$a^{2}-4$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+1\right)^{2}.

$$a^{2}+2a+1-2\left(a+1\right)-3$$

Use the distributive property to multiply -2 by a+1.

$$a^{2}+2a+1-2a-2-3$$

Combine 2a and -2a to get 0.

$$a^{2}+1-2-3$$

Subtract 2 from 1 to get -1.

$$a^{2}-1-3$$

Subtract 3 from -1 to get -4.

$$a^{2}-4$$

Expand

$$a^{2}-4$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+1\right)^{2}.

$$a^{2}+2a+1-2\left(a+1\right)-3$$

Use the distributive property to multiply -2 by a+1.

$$a^{2}+2a+1-2a-2-3$$

Combine 2a and -2a to get 0.

$$a^{2}+1-2-3$$

Subtract 2 from 1 to get -1.

$$a^{2}-1-3$$

Subtract 3 from -1 to get -4.

$$a^{2}-4$$