Solve {l}{z=3xy^7}{x=2}{y=x^2+7}

$$\left. \begin{array} { l } { z = 3 x y ^ { 7 } } \\ { x = 2 } \\ { y = x ^ { 2 } + 7 } \end{array} \right.$$

Solve for z, x, y

$$x=2$$

$$y=11$$

$$z=116923026$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$y=2^{2}+7$$

Calculate 2 to the power of 2 and get 4.

$$y=4+7$$

Add 4 and 7 to get 11.

$$y=11$$

Consider the first equation. Insert the known values of variables into the equation.

$$z=3\times 2\times 11^{7}$$

Multiply 3 and 2 to get 6.

$$z=6\times 11^{7}$$

Calculate 11 to the power of 7 and get 19487171.

$$z=6\times 19487171$$

Multiply 6 and 19487171 to get 116923026.

$$z=116923026$$

The system is now solved.

$$z=116923026 x=2 y=11$$