Solve {l}{y_{1}=x-4/4-12=x-10/5}{y_{1}-y_{2}=1}

$$\left. \begin{array} { l } { y _ { 1 } = \frac { x - 4 } { 4 } - 12 = \frac { x - 10 } { 5 } } \\ { y _ { 1 } - y _ { 2 } = 1 } \end{array} \right.$$

Solve for x

$$x=4\left(y_{1}+13\right)$$

Steps for Solving Linear Equation

Divide each term of x-4 by 4 to get \frac{1}{4}x-1.

$$y_{1}=\frac{1}{4}x-1-12$$

Subtract 12 from -1 to get -13.

$$y_{1}=\frac{1}{4}x-13$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{4}x-13=y_{1}$$

Add 13 to both sides.

$$\frac{1}{4}x=y_{1}+13$$

Multiply both sides by 4.

$$\frac{\frac{1}{4}x}{\frac{1}{4}}=\frac{y_{1}+13}{\frac{1}{4}}$$

Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.

$$x=\frac{y_{1}+13}{\frac{1}{4}}$$

Divide y_{1}+13 by \frac{1}{4} by multiplying y_{1}+13 by the reciprocal of \frac{1}{4}.

$$x=4y_{1}+52$$