Solve {l}{y(x)=x^2/1300}{x=16}

$$\left. \begin{array} { l } { y ( x ) = \frac { x ^ { 2 } } { 1300 } } \\ { x = 16 } \end{array} \right.$$

Solve for y, x

$$x=16$$

$$y=\frac{4}{325}\approx 0.012307692$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y\times 16=\frac{16^{2}}{1300}$$

Multiply both sides of the equation by 1300.

$$1300y\times 16=16^{2}$$

Multiply 1300 and 16 to get 20800.

$$20800y=16^{2}$$

Calculate 16 to the power of 2 and get 256.

$$20800y=256$$

Divide both sides by 20800.

$$y=\frac{256}{20800}$$

Reduce the fraction \frac{256}{20800} to lowest terms by extracting and canceling out 64.

$$y=\frac{4}{325}$$

The system is now solved.

$$y=\frac{4}{325} x=16$$