Solve for y, x
x=\frac{-\sqrt{169-4С}+13}{2}\text{, }y=\frac{-\sqrt{169-4С}-5}{2}
x=\frac{\sqrt{169-4С}+13}{2}\text{, }y=\frac{\sqrt{169-4С}-5}{2}\text{, }С\leq \frac{169}{4}
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