Solve {l}{y=x-20000}{0.08x+0.00y=1840}

$$\left. \begin{array} { l } { y = x - 20000 } \\ { 0.08 x + 0.00 y = 1840 } \end{array} \right.$$

Solve for y, x

$$x=23000$$

$$y=3000$$

Solution Steps

Consider the first equation. Subtract x from both sides.

$$y-x=-20000$$

Consider the second equation. Anything times zero gives zero.

$$0.08x+0=1840$$

Anything plus zero gives itself.

$$0.08x=1840$$

Divide both sides by 0.08.

$$x=\frac{1840}{0.08}$$

Expand \frac{1840}{0.08} by multiplying both numerator and the denominator by 100.

$$x=\frac{184000}{8}$$

Divide 184000 by 8 to get 23000.

$$x=23000$$

Consider the first equation. Insert the known values of variables into the equation.

$$y-23000=-20000$$

Add 23000 to both sides.

$$y=-20000+23000$$

Add -20000 and 23000 to get 3000.

$$y=3000$$

The system is now solved.

$$y=3000 x=23000$$