Solve for y, x
x=3
y=-1
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y=3^{3}-12\times 3+8
Consider the first equation. Insert the known values of variables into the equation.
y=27-12\times 3+8
Calculate 3 to the power of 3 and get 27.
y=27-36+8
Multiply -12 and 3 to get -36.
y=-9+8
Subtract 36 from 27 to get -9.
y=-1
Add -9 and 8 to get -1.
y=-1 x=3
The system is now solved.
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