Solve for y, x
x=2
y=-8
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y=2^{3}-12\times 2+8
Consider the first equation. Insert the known values of variables into the equation.
y=8-12\times 2+8
Calculate 2 to the power of 3 and get 8.
y=8-24+8
Multiply -12 and 2 to get -24.
y=-16+8
Subtract 24 from 8 to get -16.
y=-8
Add -16 and 8 to get -8.
y=-8 x=2
The system is now solved.
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