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$\estwo{y = \exponential{x}{3} - 12 x + 8}{x = -3} $
Solve for y, x
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y=\left(-3\right)^{3}-12\left(-3\right)+8
Consider the first equation. Insert the known values of variables into the equation.
y=-27-12\left(-3\right)+8
Calculate -3 to the power of 3 and get -27.
y=-27+36+8
Multiply -12 and -3 to get 36.
y=9+8
Add -27 and 36 to get 9.
y=17
Add 9 and 8 to get 17.
y=17 x=-3
The system is now solved.