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Solve for y, t
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y=2^{2}-4\times 2+3
Consider the first equation. Insert the known values of variables into the equation.
y=4-4\times 2+3
Calculate 2 to the power of 2 and get 4.
y=4-8+3
Multiply -4 and 2 to get -8.
y=-4+3
Subtract 8 from 4 to get -4.
y=-1
Add -4 and 3 to get -1.
y=-1 t=2
The system is now solved.