Solve {l}{y=ax^2-ax-2}{x=-1}{a=0.5}

$$\left. \begin{array} { l } { y = a x ^ { 2 } - a x - 2 } \\ { x = - 1 } \\ { a = 0.5 } \end{array} \right.$$

Solve for y, a, x

$$x=-1$$

$$y=-1$$

$$a=0.5$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=0.5\left(-1\right)^{2}-0.5\left(-1\right)-2$$

Calculate -1 to the power of 2 and get 1.

$$y=0.5\times 1-0.5\left(-1\right)-2$$

Multiply 0.5 and 1 to get 0.5.

$$y=0.5-0.5\left(-1\right)-2$$

Multiply -0.5 and -1 to get 0.5.

$$y=0.5+0.5-2$$

Add 0.5 and 0.5 to get 1.

$$y=1-2$$

Subtract 2 from 1 to get -1.

$$y=-1$$

The system is now solved.

$$y=-1 a=0.5 x=-1$$