Solve for y, x
x=0.645902
y=-0.199985077547113536
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y=8\times 0.645902^{3}-2\times 0.645902^{2}-7\times 0.645902+3
Consider the first equation. Insert the known values of variables into the equation.
y=8\times 0.269463463707610808-2\times 0.645902^{2}-7\times 0.645902+3
Calculate 0.645902 to the power of 3 and get 0.269463463707610808.
y=2.155707709660886464-2\times 0.645902^{2}-7\times 0.645902+3
Multiply 8 and 0.269463463707610808 to get 2.155707709660886464.
y=2.155707709660886464-2\times 0.417189393604-7\times 0.645902+3
Calculate 0.645902 to the power of 2 and get 0.417189393604.
y=2.155707709660886464-0.834378787208-7\times 0.645902+3
Multiply -2 and 0.417189393604 to get -0.834378787208.
y=1.321328922452886464-7\times 0.645902+3
Subtract 0.834378787208 from 2.155707709660886464 to get 1.321328922452886464.
y=1.321328922452886464-4.521314+3
Multiply -7 and 0.645902 to get -4.521314.
y=-3.199985077547113536+3
Subtract 4.521314 from 1.321328922452886464 to get -3.199985077547113536.
y=-0.199985077547113536
Add -3.199985077547113536 and 3 to get -0.199985077547113536.
y=-0.199985077547113536 x=0.645902
The system is now solved.
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