Solve {l}{y=3x^2-8x+5}{x=1}{dx=0.1}

$$\left. \begin{array} { l } { y = 3 x ^ { 2 } - 8 x + 5 } \\ { x = 1 } \\ { d x = 0.1 } \end{array} \right.$$

Solve for y, x, d

$$x=1$$

$$y=0$$

$$d=0.1$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=3\times 1^{2}-8+5$$

Calculate 1 to the power of 2 and get 1.

$$y=3\times 1-8+5$$

Multiply 3 and 1 to get 3.

$$y=3-8+5$$

Subtract 8 from 3 to get -5.

$$y=-5+5$$

Add -5 and 5 to get 0.

$$y=0$$

Consider the third equation. Insert the known values of variables into the equation.

$$d\times 1=0.1$$

Divide both sides by 1.

$$d=\frac{0.1}{1}$$

Expand \frac{0.1}{1} by multiplying both numerator and the denominator by 10.

$$d=\frac{1}{10}$$

The system is now solved.

$$y=0 x=1 d=\frac{1}{10}$$