Solve for y, x
x=4
y=5
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Algebra
\left. \begin{array} { l } { y = 2 x - 3 } \\ { \text { if } x = 4 } \end{array} \right.
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y=2\times 4-3
Consider the first equation. Insert the known values of variables into the equation.
y=8-3
Multiply 2 and 4 to get 8.
y=5
Subtract 3 from 8 to get 5.
y=5 x=4
The system is now solved.
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