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Solve for y, x
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y=2\times 2+\frac{8}{2^{2}}
Consider the first equation. Insert the known values of variables into the equation.
y=4+\frac{8}{2^{2}}
Multiply 2 and 2 to get 4.
y=4+\frac{8}{4}
Calculate 2 to the power of 2 and get 4.
y=4+2
Divide 8 by 4 to get 2.
y=6
Add 4 and 2 to get 6.
y=6 x=2
The system is now solved.