Solve {l}{y=-3(x+8)^2+108}{4=x}

$$\left. \begin{array} { l } { y = - 3 ( x + 8 ) ^ { 2 } + 108 } \\ { 4 = x } \end{array} \right.$$

Solve for y, x

$$x=4$$

$$y=-324$$

Solution Steps

Consider the second equation. Swap sides so that all variable terms are on the left hand side.

$$x=4$$

Consider the first equation. Insert the known values of variables into the equation.

$$y=-3\left(4+8\right)^{2}+108$$

Add 4 and 8 to get 12.

$$y=-3\times 12^{2}+108$$

Calculate 12 to the power of 2 and get 144.

$$y=-3\times 144+108$$

Multiply -3 and 144 to get -432.

$$y=-432+108$$

Add -432 and 108 to get -324.

$$y=-324$$

The system is now solved.

$$y=-324 x=4$$