Solve {l}{y=(2-2a)a^2}{a=1/3}

$$\left. \begin{array} { l } { y = ( 2 - 2 a ) a ^ { 2 } } \\ { a = \frac { 1 } { 3 } } \end{array} \right.$$

Solve for y, a

$$y=\frac{4}{27}\approx 0.148148148$$

$$a=\frac{1}{3}\approx 0.333333333$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=\left(2-2\times \frac{1}{3}\right)\times \left(\frac{1}{3}\right)^{2}$$

Multiply -2 and \frac{1}{3} to get -\frac{2}{3}.

$$y=\left(2-\frac{2}{3}\right)\times \left(\frac{1}{3}\right)^{2}$$

Subtract \frac{2}{3} from 2 to get \frac{4}{3}.

$$y=\frac{4}{3}\times \left(\frac{1}{3}\right)^{2}$$

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$y=\frac{4}{3}\times \frac{1}{9}$$

Multiply \frac{4}{3} and \frac{1}{9} to get \frac{4}{27}.

$$y=\frac{4}{27}$$

The system is now solved.

$$y=\frac{4}{27} a=\frac{1}{3}$$