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Solve for y, x
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y=-2
Consider the second equation. Add -4 and 2 to get -2.
-2=-\frac{4}{3}x+3
Consider the first equation. Insert the known values of variables into the equation.
-\frac{4}{3}x+3=-2
Swap sides so that all variable terms are on the left hand side.
-\frac{4}{3}x=-2-3
Subtract 3 from both sides.
-\frac{4}{3}x=-5
Subtract 3 from -2 to get -5.
x=-5\left(-\frac{3}{4}\right)
Multiply both sides by -\frac{3}{4}, the reciprocal of -\frac{4}{3}.
x=\frac{15}{4}
Multiply -5 and -\frac{3}{4} to get \frac{15}{4}.
y=-2 x=\frac{15}{4}
The system is now solved.