Solve {l}{y=y-8/3=y+4/2*3}{2*3}

$$\left. \begin{array} { l } { y = \frac { y - 8 } { 3 } = \frac { y + 4 } { 2 } \times 3 } \\ { 2 \times 3 } \end{array} \right.$$

Solve for y

$$y=-4$$

Steps for Solving Linear Equation

Divide each term of y-8 by 3 to get \frac{1}{3}y-\frac{8}{3}.

$$y=\frac{1}{3}y-\frac{8}{3}$$

Subtract \frac{1}{3}y from both sides.

$$y-\frac{1}{3}y=-\frac{8}{3}$$

Combine y and -\frac{1}{3}y to get \frac{2}{3}y.

$$\frac{2}{3}y=-\frac{8}{3}$$

Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.

$$y=-\frac{8}{3}\times \frac{3}{2}$$

Multiply -\frac{8}{3} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$y=\frac{-8\times 3}{3\times 2}$$

Cancel out 3 in both numerator and denominator.

$$y=\frac{-8}{2}$$

Divide -8 by 2 to get -4.

$$y=-4$$