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\frac{16}{5}=\frac{4}{3}x+4
Consider the first equation. Insert the known values of variables into the equation.
\frac{4}{3}x+4=\frac{16}{5}
Swap sides so that all variable terms are on the left hand side.
\frac{4}{3}x=\frac{16}{5}-4
Subtract 4 from both sides.
\frac{4}{3}x=-\frac{4}{5}
Subtract 4 from \frac{16}{5} to get -\frac{4}{5}.
x=-\frac{4}{5}\times \frac{3}{4}
Multiply both sides by \frac{3}{4}, the reciprocal of \frac{4}{3}.
x=-\frac{3}{5}
Multiply -\frac{4}{5} and \frac{3}{4} to get -\frac{3}{5}.
y=\frac{16}{5} x=-\frac{3}{5}
The system is now solved.