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Solve for y, x
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y=\frac{3\times 3-1}{\left(3+1\right)^{2}}
Consider the first equation. Insert the known values of variables into the equation.
y=\frac{9-1}{\left(3+1\right)^{2}}
Multiply 3 and 3 to get 9.
y=\frac{8}{\left(3+1\right)^{2}}
Subtract 1 from 9 to get 8.
y=\frac{8}{4^{2}}
Add 3 and 1 to get 4.
y=\frac{8}{16}
Calculate 4 to the power of 2 and get 16.
y=\frac{1}{2}
Reduce the fraction \frac{8}{16} to lowest terms by extracting and canceling out 8.
y=\frac{1}{2} x=3
The system is now solved.