Solve for y, x
x=4
y=\frac{1}{32}=0.03125
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y=\frac{2}{4^{3}}
Consider the first equation. Insert the known values of variables into the equation.
y=\frac{2}{64}
Calculate 4 to the power of 3 and get 64.
y=\frac{1}{32}
Reduce the fraction \frac{2}{64} to lowest terms by extracting and canceling out 2.
y=\frac{1}{32} x=4
The system is now solved.
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