Solve for y, x
x=6
y=1
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1=\frac{1}{3}x-1
Consider the first equation. Insert the known values of variables into the equation.
\frac{1}{3}x-1=1
Swap sides so that all variable terms are on the left hand side.
\frac{1}{3}x=1+1
Add 1 to both sides.
\frac{1}{3}x=2
Add 1 and 1 to get 2.
x=2\times 3
Multiply both sides by 3, the reciprocal of \frac{1}{3}.
x=6
Multiply 2 and 3 to get 6.
y=1 x=6
The system is now solved.
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