Solve {l}{xy+2=14}{y+6=2}

$$\left. \begin{array} { l } { x y + 2 = 14 } \\ { y + 6 = 2 } \end{array} \right.$$

Solve for x, y

$$x=-3$$

$$y=-4$$

Solution Steps

Consider the second equation. Subtract 6 from both sides.

$$y=2-6$$

Subtract 6 from 2 to get -4.

$$y=-4$$

Consider the first equation. Insert the known values of variables into the equation.

$$x\left(-4\right)+2=14$$

Subtract 2 from both sides.

$$x\left(-4\right)=14-2$$

Subtract 2 from 14 to get 12.

$$x\left(-4\right)=12$$

Divide both sides by -4.

$$x=\frac{12}{-4}$$

Divide 12 by -4 to get -3.

$$x=-3$$

The system is now solved.

$$x=-3 y=-4$$