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Solve for x_1, x_2, x_3
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x_{2}=-5\times 2
Consider the second equation. Multiply both sides by 2.
x_{2}=-10
Multiply -5 and 2 to get -10.
2x_{3}=20+1
Consider the third equation. Multiply both sides of the equation by 4, the least common multiple of 2,4.
2x_{3}=21
Add 20 and 1 to get 21.
x_{3}=\frac{21}{2}
Divide both sides by 2.
x_{1}=10 x_{2}=-10 x_{3}=\frac{21}{2}
The system is now solved.