Solve {l}{-5x=0}{text{Solvefor}ytext{where}}{y=x^3+2x^2}

$$\left. \begin{array} { l } { -5 x = 0 }\\ { \text{Solve for } y \text{ where} } \\ { y = x ^ {3} + 2 x ^ {2} } \end{array} \right.$$

Solve for x, y

$$y=0$$

Solution Steps

Consider the first equation. Divide both sides by -5. Zero divided by any non-zero number gives zero.

$$x=0$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=0^{3}+2\times 0^{2}$$

Calculate 0 to the power of 3 and get 0.

$$y=0+2\times 0^{2}$$

Calculate 0 to the power of 2 and get 0.

$$y=0+2\times 0$$

Multiply 2 and 0 to get 0.

$$y=0+0$$

Add 0 and 0 to get 0.

$$y=0$$

The system is now solved.

$$x=0 y=0$$