Solve for x, b
x=15
b=75
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x=15
Consider the second equation. Add 15 to both sides. Anything plus zero gives itself.
15^{2}-3b=0
Consider the first equation. Insert the known values of variables into the equation.
225-3b=0
Calculate 15 to the power of 2 and get 225.
-3b=-225
Subtract 225 from both sides. Anything subtracted from zero gives its negation.
b=\frac{-225}{-3}
Divide both sides by -3.
b=75
Divide -225 by -3 to get 75.
x=15 b=75
The system is now solved.
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