Solve {l}{x^2-14+3=y}{x=9/4}

$$\left. \begin{array} { l } { x ^ { 2 } - 14 + 3 = y } \\ { x = \frac { 9 } { 4 } } \end{array} \right.$$

Solve for x, y

$$x = \frac{9}{4} = 2\frac{1}{4} = 2.25$$

$$y = -\frac{95}{16} = -5\frac{15}{16} = -5.9375$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$\left(\frac{9}{4}\right)^{2}-14+3=y$$

Calculate \frac{9}{4} to the power of 2 and get \frac{81}{16}.

$$\frac{81}{16}-14+3=y$$

Subtract 14 from \frac{81}{16} to get -\frac{143}{16}.

$$-\frac{143}{16}+3=y$$

Add -\frac{143}{16} and 3 to get -\frac{95}{16}.

$$-\frac{95}{16}=y$$

Swap sides so that all variable terms are on the left hand side.

$$y=-\frac{95}{16}$$

The system is now solved.

$$x=\frac{9}{4} y=-\frac{95}{16}$$