Solve {l}{x^2=2y}{2x=3}

$$\left. \begin{array} { l } { x ^ { 2 } = 2 y } \\ { 2 x = 3 } \end{array} \right.$$

Solve for x, y

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

$$y = \frac{9}{8} = 1\frac{1}{8} = 1.125$$

Solution Steps

Consider the second equation. Divide both sides by 2.

$$x=\frac{3}{2}$$

Consider the first equation. Insert the known values of variables into the equation.

$$\left(\frac{3}{2}\right)^{2}=2y$$

Calculate \frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$\frac{9}{4}=2y$$

Swap sides so that all variable terms are on the left hand side.

$$2y=\frac{9}{4}$$

Divide both sides by 2.

$$y=\frac{\frac{9}{4}}{2}$$

Express \frac{\frac{9}{4}}{2} as a single fraction.

$$y=\frac{9}{4\times 2}$$

Multiply 4 and 2 to get 8.

$$y=\frac{9}{8}$$

The system is now solved.

$$x=\frac{3}{2} y=\frac{9}{8}$$