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9^{2}+49\times 9-19=y
Consider the first equation. Insert the known values of variables into the equation.
81+49\times 9-19=y
Calculate 9 to the power of 2 and get 81.
81+441-19=y
Multiply 49 and 9 to get 441.
522-19=y
Add 81 and 441 to get 522.
503=y
Subtract 19 from 522 to get 503.
y=503
Swap sides so that all variable terms are on the left hand side.
x=9 y=503
The system is now solved.