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Solve for x, y, z
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z=\frac{\sqrt{3}}{\left(2-3\right)^{2}}
Consider the third equation. Insert the known values of variables into the equation.
z=\frac{\sqrt{3}}{\left(-1\right)^{2}}
Subtract 3 from 2 to get -1.
z=\frac{\sqrt{3}}{1}
Calculate -1 to the power of 2 and get 1.
z=\sqrt{3}
Anything divided by one gives itself.
x=2 y=3 z=\sqrt{3}
The system is now solved.