Solve for x, y, z
x=2
y=1
z=-5
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2\times 2+3y=7
Consider the second equation. Insert the known values of variables into the equation.
4+3y=7
Multiply 2 and 2 to get 4.
3y=7-4
Subtract 4 from both sides.
3y=3
Subtract 4 from 7 to get 3.
y=\frac{3}{3}
Divide both sides by 3.
y=1
Divide 3 by 3 to get 1.
2+1-z=8
Consider the third equation. Insert the known values of variables into the equation.
3-z=8
Add 2 and 1 to get 3.
-z=8-3
Subtract 3 from both sides.
-z=5
Subtract 3 from 8 to get 5.
z=-5
Divide both sides by -1.
x=2 y=1 z=-5
The system is now solved.
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