Solve {l}{x=-1.183}{x=-1.18(2d_{p})}

$$\left. \begin{array} { l } { x = - 1.183 } \\ { x = - 1.18 ( 2 d _ { p } ) } \end{array} \right.$$

Solve for x, d_p

$$x=-1.183$$

$$d_{p}=\frac{1183}{2360}\approx 0.501271186$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$-1.183=-1.18\times 2d_{p}$$

Multiply -1.18 and 2 to get -2.36.

$$-1.183=-2.36d_{p}$$

Swap sides so that all variable terms are on the left hand side.

$$-2.36d_{p}=-1.183$$

Divide both sides by -2.36.

$$d_{p}=\frac{-1.183}{-2.36}$$

Expand \frac{-1.183}{-2.36} by multiplying both numerator and the denominator by 1000.

$$d_{p}=\frac{-1183}{-2360}$$

Fraction \frac{-1183}{-2360} can be simplified to \frac{1183}{2360} by removing the negative sign from both the numerator and the denominator.

$$d_{p}=\frac{1183}{2360}$$

The system is now solved.

$$x=-1.183 d_{p}=\frac{1183}{2360}$$