Solve {l}{x+y=9}{3y-2=6}

$$\left. \begin{array} { l } { x + y = 9 } \\ { 3 y - 2 = 6 } \end{array} \right.$$

Solve for x, y

$$x = \frac{19}{3} = 6\frac{1}{3} \approx 6.333333333$$

$$y = \frac{8}{3} = 2\frac{2}{3} \approx 2.666666667$$

Solution Steps

Consider the second equation. Add 2 to both sides.

$$3y=6+2$$

Add 6 and 2 to get 8.

$$3y=8$$

Divide both sides by 3.

$$y=\frac{8}{3}$$

Consider the first equation. Insert the known values of variables into the equation.

$$x+\frac{8}{3}=9$$

Subtract \frac{8}{3} from both sides.

$$x=9-\frac{8}{3}$$

Subtract \frac{8}{3} from 9 to get \frac{19}{3}.

$$x=\frac{19}{3}$$

The system is now solved.

$$x=\frac{19}{3} y=\frac{8}{3}$$