Solve {l}{x+y=500,quad0.15=t/y}{20x/500=2}

$$\left. \begin{array} { l } { x + y = 500 , \quad 0.15 = \frac { t } { y } } \\ { \frac { 20 x } { 500 } = 2 } \end{array} \right.$$

Solve for x, y, t

$$x=50$$

$$y=450$$

$$t=67.5$$

Solution Steps

Consider the third equation. Multiply both sides by 500.

$$20x=2\times 500$$

Multiply 2 and 500 to get 1000.

$$20x=1000$$

Divide both sides by 20.

$$x=\frac{1000}{20}$$

Divide 1000 by 20 to get 50.

$$x=50$$

Consider the first equation. Insert the known values of variables into the equation.

$$50+y=500$$

Subtract 50 from both sides.

$$y=500-50$$

Subtract 50 from 500 to get 450.

$$y=450$$

Consider the second equation. Insert the known values of variables into the equation.

$$0.15=\frac{t}{450}$$

Multiply both sides by 450.

$$0.15\times 450=t$$

Multiply 0.15 and 450 to get 67.5.

$$67.5=t$$

Swap sides so that all variable terms are on the left hand side.

$$t=67.5$$

The system is now solved.

$$x=50 y=450 t=67.5$$