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Solve for x, y
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x=\frac{2}{3}
Consider the second equation. Divide both sides by 3.
\frac{2}{3}+y=4
Consider the first equation. Insert the known values of variables into the equation.
y=4-\frac{2}{3}
Subtract \frac{2}{3} from both sides.
y=\frac{10}{3}
Subtract \frac{2}{3} from 4 to get \frac{10}{3}.
x=\frac{2}{3} y=\frac{10}{3}
The system is now solved.