Solve {l}{x+y=3}{8-y=2}

$$\left. \begin{array} { l } { x + y = 3 } \\ { 8 - y = 2 } \end{array} \right.$$

Solve for x, y

$$x=-3$$

$$y=6$$

Solution Steps

Consider the second equation. Subtract 8 from both sides.

$$-y=2-8$$

Subtract 8 from 2 to get -6.

$$-y=-6$$

Divide both sides by -1.

$$y=\frac{-6}{-1}$$

Fraction \frac{-6}{-1} can be simplified to 6 by removing the negative sign from both the numerator and the denominator.

$$y=6$$

Consider the first equation. Insert the known values of variables into the equation.

$$x+6=3$$

Subtract 6 from both sides.

$$x=3-6$$

Subtract 6 from 3 to get -3.

$$x=-3$$

The system is now solved.

$$x=-3 y=6$$