Solve {l}{x+y=3}{3-y=0}

$$\left. \begin{array} { l } { x + y = 3 } \\ { 3 - y = 0 } \end{array} \right.$$

Solve for x, y

$$x=0$$

$$y=3$$

Solution Steps

Consider the second equation. Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$-y=-3$$

Divide both sides by -1.

$$y=\frac{-3}{-1}$$

Fraction \frac{-3}{-1} can be simplified to 3 by removing the negative sign from both the numerator and the denominator.

$$y=3$$

Consider the first equation. Insert the known values of variables into the equation.

$$x+3=3$$

Subtract 3 from both sides.

$$x=3-3$$

Subtract 3 from 3 to get 0.

$$x=0$$

The system is now solved.

$$x=0 y=3$$