Solve for x, y, z
x=2
y=0
z=1
Share
Copied to clipboard
x=-y+2
Solve x+y=2 for x.
z-y+2=3
Substitute -y+2 for x in the equation z+x=3.
y=1-z z=y+1
Solve the second equation for y and the third equation for z.
z=1-z+1
Substitute 1-z for y in the equation z=y+1.
z=1
Solve z=1-z+1 for z.
y=1-1
Substitute 1 for z in the equation y=1-z.
y=0
Calculate y from y=1-1.
x=-0+2
Substitute 0 for y in the equation x=-y+2.
x=2
Calculate x from x=-0+2.
x=2 y=0 z=1
The system is now solved.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}