Solve {l}{x+y=100}{0.2x+0.6=50}

$$\left. \begin{array} { l } { x + y = 100 } \\ { 0.2 x + 0.6 = 50 } \end{array} \right.$$

Solve for x, y

$$x=247$$

$$y=-147$$

Solution Steps

Consider the second equation. Subtract 0.6 from both sides.

$$0.2x=50-0.6$$

Subtract 0.6 from 50 to get 49.4.

$$0.2x=49.4$$

Divide both sides by 0.2.

$$x=\frac{49.4}{0.2}$$

Expand \frac{49.4}{0.2} by multiplying both numerator and the denominator by 10.

$$x=\frac{494}{2}$$

Divide 494 by 2 to get 247.

$$x=247$$

Consider the first equation. Insert the known values of variables into the equation.

$$247+y=100$$

Subtract 247 from both sides.

$$y=100-247$$

Subtract 247 from 100 to get -147.

$$y=-147$$

The system is now solved.

$$x=247 y=-147$$