Solve {l}{x+5=3}{x^2-2y=0}

$$\left. \begin{array} { l } { x + 5 = 3 } \\ { x ^ { 2 } - 2 y = 0 } \end{array} \right.$$

Solve for x, y

$$x=-2$$

$$y=2$$

Solution Steps

Consider the first equation. Subtract 5 from both sides.

$$x=3-5$$

Subtract 5 from 3 to get -2.

$$x=-2$$

Consider the second equation. Insert the known values of variables into the equation.

$$\left(-2\right)^{2}-2y=0$$

Calculate -2 to the power of 2 and get 4.

$$4-2y=0$$

Subtract 4 from both sides. Anything subtracted from zero gives its negation.

$$-2y=-4$$

Divide both sides by -2.

$$y=\frac{-4}{-2}$$

Divide -4 by -2 to get 2.

$$y=2$$

The system is now solved.

$$x=-2 y=2$$