Solve for x, y
x=36
y = \frac{61}{3} = 20\frac{1}{3} \approx 20.333333333
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x=34+2
Consider the second equation. Add 2 to both sides.
x=36
Add 34 and 2 to get 36.
36+3y=97
Consider the first equation. Insert the known values of variables into the equation.
3y=97-36
Subtract 36 from both sides.
3y=61
Subtract 36 from 97 to get 61.
y=\frac{61}{3}
Divide both sides by 3.
x=36 y=\frac{61}{3}
The system is now solved.
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