Solve for x, y
x = \frac{33}{10} = 3\frac{3}{10} = 3.3
y=\frac{9}{10}=0.9
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10y=9
Consider the second equation. Combine y and 9y to get 10y.
y=\frac{9}{10}
Divide both sides by 10.
x+3\times \frac{9}{10}=6
Consider the first equation. Insert the known values of variables into the equation.
x+\frac{27}{10}=6
Multiply 3 and \frac{9}{10} to get \frac{27}{10}.
x=6-\frac{27}{10}
Subtract \frac{27}{10} from both sides.
x=\frac{33}{10}
Subtract \frac{27}{10} from 6 to get \frac{33}{10}.
x=\frac{33}{10} y=\frac{9}{10}
The system is now solved.
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