Solve {l}{x+3y=18}{22-3y=3}

$$\left. \begin{array} { l } { x + 3 y = 18 } \\ { 22 - 3 y = 3 } \end{array} \right.$$

Solve for x, y

$$x=-1$$

$$y = \frac{19}{3} = 6\frac{1}{3} \approx 6.333333333$$

Solution Steps

Consider the second equation. Subtract 22 from both sides.

$$-3y=3-22$$

Subtract 22 from 3 to get -19.

$$-3y=-19$$

Divide both sides by -3.

$$y=\frac{-19}{-3}$$

Fraction \frac{-19}{-3} can be simplified to \frac{19}{3} by removing the negative sign from both the numerator and the denominator.

$$y=\frac{19}{3}$$

Consider the first equation. Insert the known values of variables into the equation.

$$x+3\times \frac{19}{3}=18$$

Multiply 3 and \frac{19}{3} to get 19.

$$x+19=18$$

Subtract 19 from both sides.

$$x=18-19$$

Subtract 19 from 18 to get -1.

$$x=-1$$

The system is now solved.

$$x=-1 y=\frac{19}{3}$$