Solve {l}{x+28y+15=2(x+2)}{x+28+15=2x30}

$$\left. \begin{array} { l } { x + 28 y + 15 = 2 ( x + 2 ) } \\ { x + 28 + 15 = 2 x 30 } \end{array} \right.$$

Solve for x, y

$$x=2x_{30}-43$$

$$y=\frac{x_{30}-27}{14}$$

Steps Using Substitution

Consider the second equation. Add 28 and 15 to get 43.

$$x+43=2x_{30}$$

Subtract 43 from both sides.

$$x=2x_{30}-43$$

Substitute -43+2x_{30} for x in the other equation, -x+28y=-11.

$$-\left(2x_{30}-43\right)+28y=-11$$

Subtract 43-2x_{30} from both sides of the equation.

$$28y=2x_{30}-54$$

Divide both sides by 28.

$$y=\frac{x_{30}-27}{14}$$

The system is now solved.

$$x=2x_{30}-43,y=\frac{x_{30}-27}{14}$$