Solve {l}{x+2y=10y}{2x+2y=x-y+2}

$$\left. \begin{array} { l } { x + 2 y = 10 y } \\ { 2 x + 2 y = x - y + 2 } \end{array} \right.$$

Solve for x, y

$$x = \frac{16}{11} = 1\frac{5}{11} \approx 1.454545455$$

$$y=\frac{2}{11}\approx 0.181818182$$

Steps Using Substitution

Consider the first equation. Subtract 10y from both sides.

$$x+2y-10y=0$$

Combine 2y and -10y to get -8y.

$$x-8y=0$$

Consider the second equation. Subtract x from both sides.

$$2x+2y-x=-y+2$$

Combine 2x and -x to get x.

$$x+2y=-y+2$$

Add y to both sides.

$$x+2y+y=2$$

Combine 2y and y to get 3y.

$$x+3y=2$$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$$x-8y=0,x+3y=2$$

Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.

$$x-8y=0$$

Add 8y to both sides of the equation.

$$x=8y$$

Substitute 8y for x in the other equation, x+3y=2.

$$8y+3y=2$$

Add 8y to 3y.

$$11y=2$$

Divide both sides by 11.

$$y=\frac{2}{11}$$

Substitute \frac{2}{11} for y in x=8y. Because the resulting equation contains only one variable, you can solve for x directly.

$$x=8\times \frac{2}{11}$$

Multiply 8 times \frac{2}{11}.

$$x=\frac{16}{11}$$

The system is now solved.

$$x=\frac{16}{11},y=\frac{2}{11}$$

Steps Using Matrices

Consider the first equation. Subtract 10y from both sides.

$$x+2y-10y=0$$

Combine 2y and -10y to get -8y.

$$x-8y=0$$

Consider the second equation. Subtract x from both sides.

$$2x+2y-x=-y+2$$

Combine 2x and -x to get x.

$$x+2y=-y+2$$

Add y to both sides.

$$x+2y+y=2$$

Combine 2y and y to get 3y.

$$x+3y=2$$

Put the equations in standard form and then use matrices to solve the system of equations.

$$x-8y=0,x+3y=2$$

Write the equations in matrix form.

$$\left(\begin{matrix}1&-8\\1&3\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}0\\2\end{matrix}\right)$$

Left multiply the equation by the inverse matrix of \left(\begin{matrix}1&-8\\1&3\end{matrix}\right).

$$inverse(\left(\begin{matrix}1&-8\\1&3\end{matrix}\right))\left(\begin{matrix}1&-8\\1&3\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}1&-8\\1&3\end{matrix}\right))\left(\begin{matrix}0\\2\end{matrix}\right)$$

The product of a matrix and its inverse is the identity matrix.

$$\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}1&-8\\1&3\end{matrix}\right))\left(\begin{matrix}0\\2\end{matrix}\right)$$

Multiply the matrices on the left hand side of the equal sign.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}1&-8\\1&3\end{matrix}\right))\left(\begin{matrix}0\\2\end{matrix}\right)$$

For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the inverse matrix is \left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right), so the matrix equation can be rewritten as a matrix multiplication problem.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{3}{3-\left(-8\right)}&-\frac{-8}{3-\left(-8\right)}\\-\frac{1}{3-\left(-8\right)}&\frac{1}{3-\left(-8\right)}\end{matrix}\right)\left(\begin{matrix}0\\2\end{matrix}\right)$$

Do the arithmetic.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{3}{11}&\frac{8}{11}\\-\frac{1}{11}&\frac{1}{11}\end{matrix}\right)\left(\begin{matrix}0\\2\end{matrix}\right)$$

Multiply the matrices.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{8}{11}\times 2\\\frac{1}{11}\times 2\end{matrix}\right)$$

Do the arithmetic.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{16}{11}\\\frac{2}{11}\end{matrix}\right)$$

Extract the matrix elements x and y.

$$x=\frac{16}{11},y=\frac{2}{11}$$

Steps Using Elimination

Consider the first equation. Subtract 10y from both sides.

$$x+2y-10y=0$$

Combine 2y and -10y to get -8y.

$$x-8y=0$$

Consider the second equation. Subtract x from both sides.

$$2x+2y-x=-y+2$$

Combine 2x and -x to get x.

$$x+2y=-y+2$$

Add y to both sides.

$$x+2y+y=2$$

Combine 2y and y to get 3y.

$$x+3y=2$$

In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

$$x-8y=0,x+3y=2$$

Subtract x+3y=2 from x-8y=0 by subtracting like terms on each side of the equal sign.

$$x-x-8y-3y=-2$$

Add x to -x. Terms x and -x cancel out, leaving an equation with only one variable that can be solved.

$$-8y-3y=-2$$

Add -8y to -3y.

$$-11y=-2$$

Divide both sides by -11.

$$y=\frac{2}{11}$$

Substitute \frac{2}{11} for y in x+3y=2. Because the resulting equation contains only one variable, you can solve for x directly.

$$x+3\times \frac{2}{11}=2$$

Multiply 3 times \frac{2}{11}.

$$x+\frac{6}{11}=2$$

Subtract \frac{6}{11} from both sides of the equation.

$$x=\frac{16}{11}$$

The system is now solved.

$$x=\frac{16}{11},y=\frac{2}{11}$$